If the common difference of an AP is 5, then | vedclass

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(C) Given,the common difference of the $AP$ is $d = 5$.The $n^{th}$ term of an $AP$ is given by the formula $a_n = a + (n - 1)d$,where $a$ is the firs

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$25$

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(C) Given,the common difference of the $AP$ is $d = 5$.The $n^{th}$ term of an $AP$ is given by the formula $a_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.Now,we need to find $a_{18} - a_{13}$.$a_{18} = a + (18 - 1)d = a + 17d$$a_{13} = a + (13 - 1)d = a + 12d$Subtracting the two terms:$a_{18} - a_{13} = (a + 17d) - (a + 12d)$$a_{18} - a_{13} = 17d - 12d = 5d$Substituting the value of $d = 5$:$a_{18} - a_{13} = 5 	imes 5 = 25$.

If the common difference of an $AP$ is $5,$ then what is $a_{18}-a_{13} ?$

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