Find the HCF and LCM of 6,72,and 120 using th | vedclass

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(A) To find the $HCF$ and $LCM$ of $6$,$72$,and $120$ using prime factorization:Step $1$: Find the prime factors of each number.$6 = 2^1 	imes 3^1$$7

Vedclass · Accepted Answer

$HCF$ = $6$,$LCM$ = $360$

Vedclass · Answer

(A) To find the $HCF$ and $LCM$ of $6$,$72$,and $120$ using prime factorization:Step $1$: Find the prime factors of each number.$6 = 2^1 	imes 3^1$$72 = 2^3 	imes 3^2$$120 = 2^3 	imes 3^1 	imes 5^1$Step $2$: The $HCF$ is the product of the smallest power of each common prime factor.$HCF = 2^1 	imes 3^1 = 6$Step $3$: The $LCM$ is the product of the greatest power of each prime factor involved.$LCM = 2^3 	imes 3^2 	imes 5^1 = 8 	imes 9 	imes 5 = 360$Thus,the $HCF$ is $6$ and the $LCM$ is $360$.

Find the $HCF$ and $LCM$ of $6$,$72$,and $120$ using the prime factorization method.

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