Find the amount of water displaced by a solid | vedclass

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Question

(B) The amount of water displaced by a solid object is equal to the volume of the object.Diameter of the ball $= 28 \, cm$.Radius of the ball $(r) = \

Vedclass · Accepted Answer

$11498 \frac{2}{3} \, cm^3$

Vedclass · Answer

(B) The amount of water displaced by a solid object is equal to the volume of the object.Diameter of the ball $= 28 \, cm$.Radius of the ball $(r) = \frac{28}{2} \, cm = 14 \, cm$.Volume of the spherical ball $= \frac{4}{3} \pi r^3$.Volume $= \frac{4}{3} 	imes \frac{22}{7} 	imes (14)^3 \, cm^3$.Volume $= \frac{4}{3} 	imes \frac{22}{7} 	imes 14 	imes 14 	imes 14 \, cm^3$.Volume $= \frac{4 	imes 22 	imes 2 	imes 14 	imes 14}{3} \, cm^3 = \frac{34496}{3} \, cm^3$.Converting to mixed fraction: $34496 \div 3 = 11498$ with a remainder of $2$.So,Volume $= 11498 \frac{2}{3} \, cm^3$.Thus,the amount of water displaced is $11498 \frac{2}{3} \, cm^3$.

Find the amount of water displaced by a solid spherical ball of diameter $28 \, cm$.

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