Find the least number,which,when multiplied with $74088$ will make it a perfect square.

  • A
    $42$
  • B
    $44$
  • C
    $46$
  • D
    $48$

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The $H.C.F.$ and $L.C.M.$ of two numbers are $21$ and $84$ respectively. If the ratio of the two numbers is $1:4$,then the larger of the two numbers is

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$\frac{\sqrt{1296}}{?} = \frac{?}{2.25}$

$\frac{14}{3+\sqrt{2}}=?$

$\sqrt{5^{2} \times 14 - 6 \times 7 + (4)^{?}} = 18$

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