Find the number of terms in the finite A.P. 6 | vedclass

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Question

(A) Given $A.P.$ is $6, 5.5, 5, \ldots, -12$.Here,the first term $a = 6$.The common difference $d = 5.5 - 6 = -0.5$.The last term $a_n = -12$.The form

Vedclass · Accepted Answer

$37$

Vedclass · Answer

(A) Given $A.P.$ is $6, 5.5, 5, \ldots, -12$.Here,the first term $a = 6$.The common difference $d = 5.5 - 6 = -0.5$.The last term $a_n = -12$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values: $-12 = 6 + (n - 1)(-0.5)$.$-12 - 6 = (n - 1)(-0.5)$.$-18 = (n - 1)(-0.5)$.$n - 1 = \frac{-18}{-0.5} = 36$.$n = 36 + 1 = 37$.Thus,the number of terms in the $A.P.$ is $37$.

Find the number of terms in the finite $A.P.$ $6, 5.5, 5, \ldots, -12$.

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