Find the ratio in which the line $2x + 3y - 5 = 0$ divides the line segment joining the points $(8, -9)$ and $(2, 1)$. Also,find the coordinates of the point of division.

(A) Let the line $2x + 3y - 5 = 0$ divide the line segment joining the points $A(8, -9)$ and $B(2, 1)$ in the ratio $\lambda : 1$ at point $P$.
Using the section formula,the coordinates of $P$ are given by:
$P = \left( \frac{2\lambda + 8}{\lambda + 1}, \frac{\lambda - 9}{\lambda + 1} \right)$
Since point $P$ lies on the line $2x + 3y - 5 = 0$,we substitute these coordinates into the equation:
$2\left( \frac{2\lambda + 8}{\lambda + 1} \right) + 3\left( \frac{\lambda - 9}{\lambda + 1} \right) - 5 = 0$
Multiplying by $(\lambda + 1)$:
$2(2\lambda + 8) + 3(\lambda - 9) - 5(\lambda + 1) = 0$
$4\lambda + 16 + 3\lambda - 27 - 5\lambda - 5 = 0$
$2\lambda - 16 = 0$
$2\lambda = 16 \Rightarrow \lambda = 8$
Thus,the ratio is $8 : 1$.
Now,find the coordinates of $P$ by substituting $\lambda = 8$:
$x = \frac{2(8) + 8}{8 + 1} = \frac{16 + 8}{9} = \frac{24}{9} = \frac{8}{3}$
$y = \frac{8 - 9}{8 + 1} = \frac{-1}{9}$
The coordinates of the point of division are $(\frac{8}{3}, -\frac{1}{9})$.