If the vertices of Delta ABC are A(x_{1}, y_{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The centroid of a triangle is the point where the three medians of the triangle intersect.For a triangle with vertices $A(x_{1}, y_{1})$,$B(x_{2},

Vedclass · Accepted Answer

$\left(\frac{x_{1}+x_{2}+x_{3}}{3}, \frac{y_{1}+y_{2}+y_{3}}{3}\right)$

Vedclass · Answer

(A) The centroid of a triangle is the point where the three medians of the triangle intersect.For a triangle with vertices $A(x_{1}, y_{1})$,$B(x_{2}, y_{2})$,and $C(x_{3}, y_{3})$,the coordinates of the centroid $(G)$ are calculated by taking the arithmetic mean of the $x$-coordinates and the $y$-coordinates of the vertices.The formula for the centroid is given by:$G = \left(\frac{x_{1}+x_{2}+x_{3}}{3}, \frac{y_{1}+y_{2}+y_{3}}{3}\right)$Therefore,option $A$ is the correct answer.

If the vertices of $\Delta ABC$ are $A(x_{1}, y_{1})$,$B(x_{2}, y_{2})$,and $C(x_{3}, y_{3})$,then the centroid of $\Delta ABC$ is........

Similar Questions

Find the coordinates of the points which divide the line segment joining $A (-2, 2)$ and $B (2, 8)$ into four equal parts.

Find the coordinates of the point which divides the line segment joining the points $(-1, 7)$ and $(4, -3)$ in the ratio $2:3$.

$A (1, 2)$ and $B (2, 3)$ are the given points. Find the point $C \in \overleftrightarrow{AB}$ such that $C - A - B$ and $2 AC = 3 AB$.

If the midpoint of a line segment joining $(3, 4)$ and $(a, 8)$ is $(4, 6)$,then $a = \ldots$

$\overline{AB}$ is a diameter of a circle having the centre $P$. If $A(5, -6)$ and $B(3, -2)$,then the coordinates of $P = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module