Find the roots of the following quadratic equ | vedclass

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(B) Given equation is $\frac{2}{5} x^{2}-x-\frac{3}{5}=0$.On multiplying by $5$ on both sides,we get:$2x^{2}-5x-3=0$To factorise,we split the middle t

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$-\frac{1}{2}, 3$

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(B) Given equation is $\frac{2}{5} x^{2}-x-\frac{3}{5}=0$.On multiplying by $5$ on both sides,we get:$2x^{2}-5x-3=0$To factorise,we split the middle term $-5x$ into $-6x + x$:$2x^{2}-6x+x-3=0$Grouping the terms:$2x(x-3)+1(x-3)=0$Taking $(x-3)$ as a common factor:$(x-3)(2x+1)=0$Setting each factor to zero:$x-3=0 \Rightarrow x=3$$2x+1=0 \Rightarrow x=-\frac{1}{2}$Hence,the roots of the equation are $-\frac{1}{2}$ and $3$.

Find the roots of the following quadratic equations by the factorisation method:
$\frac{2}{5} x^{2}-x-\frac{3}{5}=0$

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Find the roots of the following quadratic equations by the factorisation method:$\frac{2}{5} x^{2}-x-\frac{3}{5}=0$