Find the value of theta,if |tan theta|=tan th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given equation: $|	an 	heta| = 	an 	heta + \sec 	heta$. Case $1$: If $	an 	heta \ge 0$,then $	an 	heta = 	an 	heta + \sec 	heta$,which

Vedclass · Accepted Answer

$\frac{11\pi}{6}$

Vedclass · Answer

(B) Given equation: $|	an 	heta| = 	an 	heta + \sec 	heta$. Case $1$: If $	an 	heta \ge 0$,then $	an 	heta = 	an 	heta + \sec 	heta$,which implies $\sec 	heta = 0$. This has no solution. Case $2$: If $	an 	heta Substituting $	an 	heta = \frac{\sin 	heta}{\cos 	heta}$ and $\sec 	heta = \frac{1}{\cos 	heta}$,we get $2\sin 	heta + 1 = 0$,so $\sin 	heta = -\frac{1}{2}$. Since $	an 	heta Checking $	an 	heta For $	heta = \frac{7\pi}{6}$,$	an 	heta = 	an(\frac{7\pi}{6}) = \frac{1}{\sqrt{3}} > 0$ (Reject). For $	heta = \frac{11\pi}{6}$,$	an 	heta = 	an(\frac{11\pi}{6}) = -\frac{1}{\sqrt{3}} Thus,the solution is $	heta = \frac{11\pi}{6}$.

Find the value of $\theta$,if $|\tan \theta|=\tan \theta+\frac{1}{\cos \theta}$ and $\theta \in[0, 2\pi]-\{\pm \frac{\pi}{2}\}$

Similar Questions

The general solution of $1+\sin ^{2} x=3 \sin x \cdot \cos x$,where $\tan x \neq \frac{1}{2}$,is

The set of values of $x$ for which the expression $\frac{\tan 3x - \tan 2x}{1 + \tan 3x \tan 2x} = 1$ is

Find the general solution of $3 \sin^4(\theta) + \cos^4(\theta) = 1$.

If $\cos(\alpha - \beta) = 1$ and $\cos(\alpha + \beta) = \frac{1}{e}$,where $-\pi < \alpha, \beta < \pi$,then the total number of ordered pairs $(\alpha, \beta)$ is:

If $\cos 6\theta + \cos 4\theta + \cos 2\theta + 1 = 0$,where $0 < \theta < 180^\circ$,then $\theta = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module