$A \neq 0$ અને $x < 0$ માટે,$\lim _{n \rightarrow \infty} \frac{\sin x - e^{n x}}{1 + A e^{n x}}$ ની કિંમત શોધો.

  • A
    $\frac{1}{A}$
  • B
    $\sin x$
  • C
    $-\frac{1}{A}$
  • D
    $-\sin x$

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$\lim _{x \rightarrow 0} \frac{(1-e^x) \sin x}{x^2+x^3}$ ની કિંમત શોધો.

જો $a = \lim_{n \rightarrow \infty} \frac{1+2+3+\ldots+n}{n^2}$ અને $b = \lim_{n \rightarrow \infty} \frac{1^2+2^2+3^2+\ldots+n^2}{n^3}$ હોય,તો

$\mathop {\lim }\limits_{y \to 0} \frac{{\sqrt {1 + \sqrt {1 + {y^4}} } - \sqrt 2 }}{{{y^4}}} = $

જો વિધેય $f$ એ $f(x) = \frac{\cot^3 x - \tan x}{\cos(x + \pi/4)}$ દ્વારા $x \neq \pi/4$ માટે વ્યાખ્યાયિત હોય,તો $\lim_{x \rightarrow \pi/4} f(x) = $

$\mathop {\lim }\limits_{x \to 0} \frac{{{y^2}}}{x}$ ની કિંમત શોધો,જ્યાં ${y^2} = ax + b{x^2} + c{x^3}$.

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