(A) In single slit diffraction,the condition for the first minima on either side of the central maxima is given by $a \sin \theta = \pm \lambda$.For s

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(A) In single slit diffraction,the condition for the first minima on either side of the central maxima is given by $a \sin \theta = \pm \lambda$.For small angles,$\sin \theta \approx \theta = \frac{\lambda}{a}$.The distance of the first minima from the center of the screen is $y = D \tan \theta \approx D \theta = \frac{D \lambda}{a}$.The central maxima lies between the first minima on both sides,so its total width is $2y = \frac{2D \lambda}{a}$.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

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For a parallel beam of monochromatic light of wavelength $\lambda$,diffraction is produced by a single slit whose width $a$ is of the order of the wavelength of the light. If $D$ is the distance of the screen from the slit,the width of the central maxima will be

AIPMT 2015 All AIPMT

A
$\frac{2D\lambda}{a}$
B
$\frac{D\lambda}{a}$
C
$\frac{Da}{\lambda}$
D
$\frac{2Da}{\lambda}$

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Wave Optics

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Single Slit Diffraction of Light

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Assertion: The clouds in the sky generally appear to be whitish.
Reason: Diffraction due to clouds is efficient in equal measure at all wavelengths.

EasyAIIMS 2005

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$A$ parallel beam of monochromatic light of wavelength $600 \,nm$ passes through a single slit of $0.4 \,mm$ width. The angular divergence corresponding to the second-order minima would be $...... \times 10^{-3} \,rad$.

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$A$ plane wavefront of wavelength $6 \times 10^{-7} \,m$ is incident on a slit of width $0.4 \,mm$. $A$ convex lens of focal length $0.8 \,m$ is placed behind the slit to form a diffraction pattern on a screen. What is the linear width of the second secondary maximum in $mm$?

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$A$ light wave of wavelength $\lambda$ is incident on a slit of width $d$. The resulting diffraction pattern is observed on a screen at a distance $D$. If the linear width of the principal maxima is equal to the width of the slit,then the distance $D$ is:

MediumMHT CET 2022

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$A$ beam of light having wavelength $5400 \text{ Å}$ from a distant source falls on a single slit $0.96 \text{ mm}$ wide and the resultant diffraction pattern is observed on a screen $2 \text{ m}$ away. What is the distance between the first dark fringe on either side of the central bright fringe (in $\text{mm}$)?

MediumMHT CET 2021

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For a parallel beam of monochromatic light of wavelength $\lambda$,diffraction is produced by a single slit whose width $a$ is of the order of the wavelength of the light. If $D$ is the distance of the screen from the slit,the width of the central maxima will be

Similar Questions

Assertion: The clouds in the sky generally appear to be whitish.Reason: Diffraction due to clouds is efficient in equal measure at all wavelengths.

$A$ parallel beam of monochromatic light of wavelength $600 \,nm$ passes through a single slit of $0.4 \,mm$ width. The angular divergence corresponding to the second-order minima would be $...... \times 10^{-3} \,rad$.

$A$ plane wavefront of wavelength $6 \times 10^{-7} \,m$ is incident on a slit of width $0.4 \,mm$. $A$ convex lens of focal length $0.8 \,m$ is placed behind the slit to form a diffraction pattern on a screen. What is the linear width of the second secondary maximum in $mm$?

$A$ light wave of wavelength $\lambda$ is incident on a slit of width $d$. The resulting diffraction pattern is observed on a screen at a distance $D$. If the linear width of the principal maxima is equal to the width of the slit,then the distance $D$ is:

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Assertion: The clouds in the sky generally appear to be whitish.
Reason: Diffraction due to clouds is efficient in equal measure at all wavelengths.