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(B) In an equilateral triangle with side length $a$,the altitude divides the base into two equal parts of length $\frac{a}{2}$.By applying the Pythago

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$\frac{\sqrt{3}}{2} a$

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(B) In an equilateral triangle with side length $a$,the altitude divides the base into two equal parts of length $\frac{a}{2}$.By applying the Pythagorean theorem in one of the resulting right-angled triangles:$h^{2} + (\frac{a}{2})^{2} = a^{2}$$h^{2} + \frac{a^{2}}{4} = a^{2}$$h^{2} = a^{2} - \frac{a^{2}}{4}$$h^{2} = \frac{3a^{2}}{4}$Taking the square root of both sides:$h = \frac{\sqrt{3}}{2} a$Thus,the length of the altitude is $\frac{\sqrt{3}}{2} a$.

For an equilateral triangle,each of whose side is $a$,the length of any altitude of that triangle is ...........

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