For each of the following,find a quadratic polynomial whose sum and product of the zeroes are $\frac{21}{8}$ and $\frac{5}{16}$ respectively. Also,find the zeroes of these polynomials by factorisation.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) Given that,the sum of zeroes $S = \frac{21}{8}$ and the product of zeroes $P = \frac{5}{16}$.
The required quadratic polynomial is given by $f(x) = k(x^2 - Sx + P)$,where $k$ is a constant. Taking $k = 16$ to clear the denominators:
$f(x) = 16(x^2 - \frac{21}{8}x + \frac{5}{16}) = 16x^2 - 42x + 5$.
To find the zeroes,set $f(x) = 0$:
$16x^2 - 42x + 5 = 0$.
Splitting the middle term: $16x^2 - 40x - 2x + 5 = 0$.
$8x(2x - 5) - 1(2x - 5) = 0$.
$(8x - 1)(2x - 5) = 0$.
Thus,the zeroes are $x = \frac{1}{8}$ and $x = \frac{5}{2}$.

Explore More

Similar Questions

If $x+4$ is a factor of the polynomial $x^{2}+7x+m$,then $m = $ . . . . . .

The zero of the linear polynomial $p(x) = 3x - 6$ is $\ldots$

Find the zeros of the following quadratic polynomial: $-21x^2 + 16x + 5$.

If one zero of the quadratic polynomial $x^{2}+3x+k$ is $2$,then the value of $k$ is

Obtain the quadratic or the cubic polynomial as the case may be in the standard form with the following coefficients: $a=2, b=3, c=-5, d=0$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo