For the shown diagram,find the ratio of $R_1: R_2$.

$A$ large open-top water tank is completely filled with water. $A$ small hole of diameter $4 \,mm$ is made $10 \,m$ below the water level. The flow rate of water through the hole is (Acceleration due to gravity $= 10 \,m/s^2$)

State Torricelli's law.

$A$ cylindrical vessel of cross-section $A$ contains water to a height $h$. There is a hole in the bottom of radius $a$. The time in which it will be emptied is

Tanks $A$ and $B$ open at the top contain two different liquids up to a certain height. $A$ hole is made in the wall of each tank at a depth $h$ from the surface of the liquid. The area of the hole in $B$ is twice that of the hole in $A$. If the liquid mass flux through each hole is equal,then the ratio of the densities of the liquids,$\rho_A / \rho_B$,is:

$A$ wide vessel with a small hole at the bottom is filled with two liquids. The density and height of one liquid are $\rho_1$ and $h_1$ and that of the other are $\rho_2$ and $h_2$ $(\rho_1 > \rho_2)$. The velocity of the liquid coming out of the hole is: