For the tetrahedral complex [MnBr_4]^{2-}, th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The central metal ion is $Mn^{2+}$.The atomic number of $Mn$ is $25$, so the electronic configuration of $Mn^{2+}$ is $[Ar] 3d^5$.In the tetrahedr

Vedclass · Accepted Answer

$5.9$

Vedclass · Answer

(B) The central metal ion is $Mn^{2+}$.The atomic number of $Mn$ is $25$, so the electronic configuration of $Mn^{2+}$ is $[Ar] 3d^5$.In the tetrahedral complex $[MnBr_4]^{2-}$, $Br^-$ is a weak field ligand, so the electrons remain unpaired.Number of unpaired electrons $(n)$ = $5$.The spin-only magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$.$\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \ BM$.

For the tetrahedral complex $[MnBr_4]^{2-}$, the spin-only magnetic moment value is $....$ (At. no. of $Mn = 25$) (in $BM$)

Similar Questions

Which of the following coordination compounds does not exhibit optical isomerism?

The spin-only magnetic moment of a divalent ion in aqueous solution (atomic number $29$) is ...... $BM.$

For an octahedral complex $MX_{4}Y_{2}$ ($M=$ a transition metal,$X$ and $Y$ are monodentate achiral ligands),the correct statement among the following is

$[Co(NH_3)Cl(en)_2]^{2+}$ shows two geometrical isomers,$cis$ and $trans$. Which of the following statements is correct?

The correct order of magnetic moments (spin values in $BM$) among the following is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module