From the following polynomials,find out which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine if $(x-1)$ is a factor of the polynomial $p(x) = x^{3}+6x^{2}-9x-14$,we use the Factor Theorem.According to the Factor Theorem,$(x-c)

Vedclass · Accepted Answer

No

Vedclass · Answer

(B) To determine if $(x-1)$ is a factor of the polynomial $p(x) = x^{3}+6x^{2}-9x-14$,we use the Factor Theorem.According to the Factor Theorem,$(x-c)$ is a factor of $p(x)$ if $p(c) = 0$.Here,$c = 1$.Substitute $x = 1$ into the polynomial:$p(1) = (1)^{3} + 6(1)^{2} - 9(1) - 14$$p(1) = 1 + 6 - 9 - 14$$p(1) = 7 - 23$$p(1) = -16$Since $p(1) 
eq 0$,$(x-1)$ is not a factor of the given polynomial.

From the following polynomials,find out which of them has $(x-1)$ as a factor:
$x^{3}+6x^{2}-9x-14$

Similar Questions

Examine whether $x+2$ is a factor of $x^{3}+3x^{2}+5x+6$ and of $2x+4$.

Check whether $p(x)$ is a multiple of $g(x)$ or not,where $p(x) = x^{3} - x + 1$ and $g(x) = 2 - 3x$.

Factorise : $x^{3}-3 x^{2}-9 x-5$

If $(x-1)$ is a factor of $x^{3}+7x^{2}+ax-3$,then find the value of $a$.

Factorise $25 x^{2}+25 x+6$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

From the following polynomials,find out which of them has $(x-1)$ as a factor:$x^{3}+6x^{2}-9x-14$