General solution of tan 5theta = cot 2theta i | vedclass

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Question

(A) Given the equation $	an 5	heta = \cot 2	heta$. We know that $\cot 2	heta = 	an \left( \frac{\pi}{2} - 2	heta ight)$. So,$	an 5	heta =

Vedclass · Accepted Answer

$	heta = \frac{n\pi}{7} + \frac{\pi}{14}$

Vedclass · Answer

(A) Given the equation $	an 5	heta = \cot 2	heta$. We know that $\cot 2	heta = 	an \left( \frac{\pi}{2} - 2	heta ight)$. So,$	an 5	heta = 	an \left( \frac{\pi}{2} - 2	heta ight)$. The general solution for $	an x = 	an \alpha$ is $x = n\pi + \alpha$. Therefore,$5	heta = n\pi + \frac{\pi}{2} - 2	heta$. Adding $2	heta$ to both sides,we get $7	heta = n\pi + \frac{\pi}{2}$. Dividing by $7$,we get $	heta = \frac{n\pi}{7} + \frac{\pi}{14}$.

General solution of $\tan 5\theta = \cot 2\theta$ is (where $n \in \mathbb{Z}$)

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