Glucose,when heated with CH_3OH in the presen | vedclass

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(C) Glucose exists in a cyclic hemiacetal form in equilibrium with its open-chain structure. When glucose is treated with methanol $(CH_3OH)$ in the p

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$A$ ring structure

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(C) Glucose exists in a cyclic hemiacetal form in equilibrium with its open-chain structure. When glucose is treated with methanol $(CH_3OH)$ in the presence of dry $HCl$ gas,the hemiacetal hydroxyl group (at $C_1$) reacts with methanol to form an acetal,known as a methyl glucoside. The formation of two isomeric products,$\alpha$-methyl glucoside and $\beta$-methyl glucoside,is possible only because the $C_1$ carbon is a chiral center in the cyclic (ring) structure of glucose. Therefore,the presence of a ring structure is responsible for the formation of these two glucosides.

List-$I$ (Glycosidic linkage)	List-$II$ (Polysaccharide)
$A$. $\alpha-1,4$	$I$. Amylose
$B$. $\beta-1,4$	$II$. Cellulose
$C$. $\alpha-1,4, \alpha-1,6$	$III$. Amylopectin

Glucose,when heated with $CH_3OH$ in the presence of dry $HCl$ gas,gives $\alpha$ and $\beta$-methyl glucosides because it contains:

Similar Questions

Assertion $(A)$: Both Glucose and Fructose have the same $D$-configuration.
Reason $(R)$: Both Glucose and Fructose are dextrorotatory.
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Match the following:
List-$I$ (Glycosidic linkage) List-$II$ (Polysaccharide)
$A$. $\alpha-1,4$ $I$. Amylose
$B$. $\beta-1,4$ $II$. Cellulose
$C$. $\alpha-1,4, \alpha-1,6$ $III$. Amylopectin

Which of the following statements is incorrect?

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