How far apart are the points (2,0,0) and (-3, | vedclass

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(C) Let the points be $A = (2, 0, 0)$ and $B = (-3, 0, 0)$.Using the distance formula between two points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ in $3

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) Let the points be $A = (2, 0, 0)$ and $B = (-3, 0, 0)$.Using the distance formula between two points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ in $3D$ space:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$Substituting the values:$d = \sqrt{(-3 - 2)^2 + (0 - 0)^2 + (0 - 0)^2}$$d = \sqrt{(-5)^2 + 0 + 0}$$d = \sqrt{25} = 5$Thus,the distance between the points is $5$ units.

How far apart are the points $(2,0,0)$ and $(-3,0,0)$?

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