Identify $B$ formed in the reaction: $Cl-(CH_2)_4-Cl$ $\xrightarrow{\text{excess } NH_3} A$ $\xrightarrow{NaOH} B + H_2O + NaCl$

  • A
    $Cl-(CH_2)_4-NH_2$
  • B
    $H_2N-(CH_2)_4-NH_2$
  • C
    $Cl^{-}H_3N^{+}-(CH_2)_4-NH_3^{+}Cl^{-}$
  • D
    $CH_3-CH_2-CH_2-CH_2-NH_2$

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