Identify the correct decreasing order of wavelength of light absorbed for the following complex ions:
$I. [Co(H_2O)_6]^{3+}$
$II. [Co(CN)_6]^{3-}$
$III. [CoI_6]^{3-}$
$IV. [Co(en)_3]^{3+}$

  • A
    $III > I > IV > II$
  • B
    $II > IV > I > III$
  • C
    $III > I > II > IV$
  • D
    $I > III > IV > II$

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Similar Questions

Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex?
$A$. $d_{xy} = d_{xz} > d_{x^2-y^2}$
$B$. $d_{xy} = d_{yz} > d_{z^2}$
$C$. $d_{x^2-y^2} > d_{z^2} > d_{xz}$
$D$. $d_{x^2-y^2} = d_{z^2}$
Choose the correct answer from the given below:

The complex that has the highest crystal field splitting energy $(\Delta)$ is

Identify the correct trend given below.
(Atomic No. $= Ti : 22, Cr : 24$ and $Mo : 42$)

In the spectrochemical series, the positions occupied by the ligands $Cl^{-}$, $OH^{-}$, and $CN^{-}$ in increasing order of their crystal field splitting power are:

The $d-$orbital electronic configuration of the complex among $[Co(en)_3]^{3+}$,$[CoF_6]^{3-}$,$[Mn(H_2O)_6]^{2+}$ and $[Zn(H_2O)_6]^{2+}$ that has the highest $CFSE$ is $:$

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