Identify the element having lowest first ioni | vedclass

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(A) The ionization enthalpy $(I.E.)$ decreases down the group due to an increase in atomic size. Therefore,the $I.E.$ of $Te$ is higher than that of $

Vedclass · Accepted Answer

$Po$

Vedclass · Answer

(A) The ionization enthalpy $(I.E.)$ decreases down the group due to an increase in atomic size. Therefore,the $I.E.$ of $Te$ is higher than that of $Po$. Across a period,$I.E.$ increases with an increase in atomic number. Comparing the given elements,$Po$ (Polonium) is in Group $16$ and Period $6$,$Te$ (Tellurium) is in Group $16$ and Period $5$,$Br$ (Bromine) is in Group $17$ and Period $4$,and $Kr$ (Krypton) is in Group $18$ and Period $4$. Since $I.E.$ increases from left to right across a period and decreases down a group,$Po$ has the lowest $I.E.$ among the given elements.

Identify the element having lowest first ionization enthalpy.

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