If m and e are the mass and charge of the rev | vedclass

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(D) The total energy $(E)$ of an electron in a hydrogen atom is the sum of its kinetic energy $(K.E.)$ and potential energy $(P.E.)$.For an electron i

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$-\frac{1}{2} \frac{e^2}{r}$

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(D) The total energy $(E)$ of an electron in a hydrogen atom is the sum of its kinetic energy $(K.E.)$ and potential energy $(P.E.)$.For an electron in an orbit of radius $r$,the electrostatic potential energy is given by $P.E. = -\frac{e^2}{r}$.The kinetic energy is given by $K.E. = \frac{1}{2} \frac{e^2}{r}$.Therefore,the total energy is $E = K.E. + P.E. = \frac{e^2}{2r} - \frac{e^2}{r} = -\frac{e^2}{2r}$.

If $m$ and $e$ are the mass and charge of the revolving electron in the orbit of radius $r$ for a hydrogen atom,the total energy of the revolving electron will be:

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