If $r$ denotes the distance between the sun and the earth,then the angular momentum of the earth around the sun is proportional to

The height of a geostationary satellite is approximately ........ $km$.

Two planets,$A$ and $B$,are orbiting a common star in circular orbits of radii $R_A$ and $R_B$,respectively,with $R_B = 2 R_A$. The planet $B$ is $4 \sqrt{2}$ times more massive than planet $A$. The ratio $\left(\frac{L_B}{L_A}\right)$ of angular momentum $(L_B)$ of planet $B$ to that of planet $A$ $(L_A)$ is closest to integer . . . . . . .

$A$ geostationary satellite is revolving around the Earth. If the radius of the Earth is $R$ and the angular speed of the Earth about its own axis is $\omega$,then the radius of the orbit of the geostationary satellite is ($g =$ acceleration due to gravity).

$A$ body moves in a circular orbit of radius $R$ under the action of a central force. The potential due to the central force is given by $V(r) = kr$ ($k$ is a positive constant). The period of revolution of the body is proportional to:

The kinetic energy of a revolving satellite of mass $m$ at a height equal to thrice the radius of the Earth $R$ is: