If 2 = x + frac{1}{1 + frac{1}{3 + frac{1}{4} | vedclass

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(D) First,simplify the continued fraction part: $\frac{1}{3 + \frac{1}{4}} = \frac{1}{\frac{13}{4}} = \frac{4}{13}$.Next,add the $1$ in the denominato

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$\frac{21}{17}$

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(D) First,simplify the continued fraction part: $\frac{1}{3 + \frac{1}{4}} = \frac{1}{\frac{13}{4}} = \frac{4}{13}$.Next,add the $1$ in the denominator: $1 + \frac{4}{13} = \frac{17}{13}$.Then,take the reciprocal: $\frac{1}{\frac{17}{13}} = \frac{13}{17}$.Finally,solve for $x$: $x = 2 - \frac{13}{17} = \frac{34 - 13}{17} = \frac{21}{17}$.

If $2 = x + \frac{1}{1 + \frac{1}{3 + \frac{1}{4}}}$,then the value of $x$ is

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