If $f(x) = 4x^3 + 3x^2 + 3x + 4$,then $x^3 f\left( \frac{1}{x} \right)$ is

  • A
    $f(-x)$
  • B
    $\frac{1}{f(x)}$
  • C
    $\left( f\left( \frac{1}{x} \right) \right)^2$
  • D
    $f(x)$

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