If (x-2)(x-p) = x^{2}-ax+6,then the value of | vedclass

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(C) Given the equation: $(x-2)(x-p) = x^{2}-ax+6$Expanding the left side: $x^{2} - px - 2x + 2p = x^{2} - ax + 6$$x^{2} - (p+2)x + 2p = x^{2} - ax + 6

Vedclass · Accepted Answer

$2$

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(C) Given the equation: $(x-2)(x-p) = x^{2}-ax+6$Expanding the left side: $x^{2} - px - 2x + 2p = x^{2} - ax + 6$$x^{2} - (p+2)x + 2p = x^{2} - ax + 6$Comparing the coefficients of $x$ and the constant terms on both sides:For the constant term: $2p = 6 \implies p = 3$For the coefficient of $x$: $-(p+2) = -a \implies a = p+2$Substituting $p=3$ into the expression for $a$: $a = 3+2 = 5$Now,calculate $(a-p)$: $a-p = 5-3 = 2$

If $(x-2)(x-p) = x^{2}-ax+6$,then the value of $(a-p)$ is

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