If sin theta + sin^2 theta = 1,then cos^2 the | vedclass

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(A) Given: $\sin 	heta + \sin^2 	heta = 1$We know that $\sin^2 	heta = 1 - \cos^2 	heta$. Substituting this into the equation:$\sin 	heta + (1 -

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$1$

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(A) Given: $\sin 	heta + \sin^2 	heta = 1$We know that $\sin^2 	heta = 1 - \cos^2 	heta$. Substituting this into the equation:$\sin 	heta + (1 - \cos^2 	heta) = 1$Subtracting $1$ from both sides:$\sin 	heta - \cos^2 	heta = 0$Therefore,$\sin 	heta = \cos^2 	heta$.Now,square both sides:$\sin^2 	heta = (\cos^2 	heta)^2$$\sin^2 	heta = \cos^4 	heta$Substitute $\sin^2 	heta = 1 - \cos^2 	heta$ into the equation:$1 - \cos^2 	heta = \cos^4 	heta$Rearranging the terms:$1 = \cos^2 	heta + \cos^4 	heta$Thus,the value of $\cos^2 	heta + \cos^4 	heta$ is $1$.

If $\sin \theta + \sin^2 \theta = 1$,then $\cos^2 \theta + \cos^4 \theta$ is equal to

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