If tan A + cot A = 2,then the value of tan^{1 | vedclass

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(C) Given the equation $	an A + \cot A = 2$.We know that $\cot A = \frac{1}{	an A}$.Substituting this into the equation,we get $	an A + \frac{1}{

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$2$

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(C) Given the equation $	an A + \cot A = 2$.We know that $\cot A = \frac{1}{	an A}$.Substituting this into the equation,we get $	an A + \frac{1}{	an A} = 2$.Let $	an A = x$,then $x + \frac{1}{x} = 2$,which simplifies to $x^2 - 2x + 1 = 0$.This is $(x - 1)^2 = 0$,so $x = 1$.Thus,$	an A = 1$,which implies $\cot A = 1$.Now,we need to find the value of $	an^{10} A + \cot^{10} A$.Substituting the values,we get $(1)^{10} + (1)^{10} = 1 + 1 = 2$.

If $\tan A + \cot A = 2$,then the value of $\tan^{10} A + \cot^{10} A$ is

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