If 7 sin a = 24 cos a,then the value of 14 ta | vedclass

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(B) Given the equation $7 \sin a = 24 \cos a$.Dividing both sides by $\cos a$,we get $\frac{\sin a}{\cos a} = 	an a = \frac{24}{7}$.Using the trigono

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$2$

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(B) Given the equation $7 \sin a = 24 \cos a$.Dividing both sides by $\cos a$,we get $\frac{\sin a}{\cos a} = 	an a = \frac{24}{7}$.Using the trigonometric identity $\sec^2 a = 1 + 	an^2 a$,we have $\sec^2 a = 1 + (\frac{24}{7})^2 = 1 + \frac{576}{49} = \frac{49 + 576}{49} = \frac{625}{49}$.Taking the square root,$\sec a = \frac{25}{7}$.Since $\cos a = \frac{1}{\sec a}$,we have $\cos a = \frac{7}{25}$.Now,substitute these values into the expression $14 	an a - 75 \cos a - 7 \sec a$:$= 14(\frac{24}{7}) - 75(\frac{7}{25}) - 7(\frac{25}{7})$$= 2(24) - 3(7) - 25$$= 48 - 21 - 25$$= 48 - 46 = 2$.

If $7 \sin a = 24 \cos a$,then the value of $14 \tan a - 75 \cos a - 7 \sec a$ is equal to:

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