If A={1,2,3}, B={2,3,4}, C={1,3,4} and D={2,4 | vedclass

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(B) Given sets are $A=\{1,2,3\}, B=\{2,3,4\}, C=\{1,3,4\},$ and $D=\{2,4,5\}.$First,we find the Cartesian products:$(A 	imes B) = \{(1,2), (1,3), (1,

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$(A \cap C) 	imes (B \cap D)$

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(B) Given sets are $A=\{1,2,3\}, B=\{2,3,4\}, C=\{1,3,4\},$ and $D=\{2,4,5\}.$First,we find the Cartesian products:$(A 	imes B) = \{(1,2), (1,3), (1,4), (2,2), (2,3), (2,4), (3,2), (3,3), (3,4)\}$$(C 	imes D) = \{(1,2), (1,4), (1,5), (3,2), (3,4), (3,5), (4,2), (4,4), (4,5)\}$Now,find the intersection of these two sets:$(A 	imes B) \cap (C 	imes D) = \{(1,2), (1,4), (3,2), (3,4)\}$Next,evaluate the expression in option $B$:$(A \cap C) = \{1,3\} \cap \{1,3,4\} = \{1,3\}$$(B \cap D) = \{2,3,4\} \cap \{2,4,5\} = \{2,4\}$$(A \cap C) 	imes (B \cap D) = \{1,3\} 	imes \{2,4\} = \{(1,2), (1,4), (3,2), (3,4)\}$Since both results are identical,the correct option is $(A \cap C) 	imes (B \cap D).$

If $A=\{1,2,3\}, B=\{2,3,4\}, C=\{1,3,4\}$ and $D=\{2,4,5\},$ then $(A \times B) \cap (C \times D) =$

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