If text{g.c.d.}(12, 40) = 40 + 4x,then x = do | vedclass

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(D) The greatest common divisor (g.c.d.) of $12$ and $40$ is calculated as follows:Prime factorization of $12 = 2^2 	imes 3^1$.Prime factorization of

Vedclass · Accepted Answer

$-9$

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(D) The greatest common divisor (g.c.d.) of $12$ and $40$ is calculated as follows:Prime factorization of $12 = 2^2 	imes 3^1$.Prime factorization of $40 = 2^3 	imes 5^1$.The g.c.d. is the product of the smallest powers of common prime factors: $2^2 = 4$.Given the equation: $	ext{g.c.d.}(12, 40) = 40 + 4x$.Substituting the value: $4 = 40 + 4x$.Subtracting $40$ from both sides: $4 - 40 = 4x$.$-36 = 4x$.Dividing by $4$: $x = -9$.

If $\text{g.c.d.}(12, 40) = 40 + 4x$,then $x = \dots$

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