If x+3 is a factor of x^{3}+12x^{2}+ax+60,the | vedclass

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(D) Let $p(x) = x^{3} + 12x^{2} + ax + 60$.Since $(x+3)$ is a factor of $p(x)$,by the Factor Theorem,$p(-3) = 0$.Substituting $x = -3$ into the polyno

Vedclass · Accepted Answer

$47$

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(D) Let $p(x) = x^{3} + 12x^{2} + ax + 60$.Since $(x+3)$ is a factor of $p(x)$,by the Factor Theorem,$p(-3) = 0$.Substituting $x = -3$ into the polynomial:$(-3)^{3} + 12(-3)^{2} + a(-3) + 60 = 0$$-27 + 12(9) - 3a + 60 = 0$$-27 + 108 - 3a + 60 = 0$$141 - 3a = 0$$3a = 141$$a = 47$.

If $x+3$ is a factor of $x^{3}+12x^{2}+ax+60$,then $a = \ldots$

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