If $p(3) = 0$ for a polynomial $p(x)$,state one factor of $p(x)$.
(A) According to the Factor Theorem,if $p(a) = 0$ for a polynomial $p(x)$,then $(x - a)$ is a factor of $p(x)$.
Given that $p(3) = 0$,we substitute $a = 3$ into the theorem.
Therefore,$(x - 3)$ is a factor of $p(x)$.
Given that $p(3) = 0$,we substitute $a = 3$ into the theorem.
Therefore,$(x - 3)$ is a factor of $p(x)$.
Explore More
Similar Questions
Find the zeroes of the polynomial in each of the following:
$g(x) = 3 - 6x$
$g(x) = 3 - 6x$
Easy
View SolutionThe zero of the polynomial $p(x) = bx + m$ is $\ldots \ldots \ldots$
Easy
View SolutionFind the zero of the polynomial: $p(x) = 3x$
Easy
View SolutionVerify whether the following are zeroes of the polynomial indicated against them:
$p(x) = 3x^2 - 1, x = -\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$
$p(x) = 3x^2 - 1, x = -\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$
Easy
View SolutionWith the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x + 6$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo