If $\alpha, \beta$ and $\gamma$ are the roots of $x^3 + 8 = 0$,then the equation whose roots are $\alpha^2, \beta^2$ and $\gamma^2$ is

  • A
    $x^3 - 8 = 0$
  • B
    $x^3 - 16 = 0$
  • C
    $x^3 + 64 = 0$
  • D
    $x^3 - 64 = 0$

Explore More

Similar Questions

If $\omega$ is a complex cube root of unity,then $(x - y)(x\omega - y)(x\omega^2 - y) = $

If $\omega \neq 1$ is a cube root of unity,then one root among the $7^{\text{th}}$ roots of $(1+\omega)$ is

If $\alpha$ and $\beta$ are the roots of the equation $x^2-2x+4=0$,then $\alpha^{12}+\beta^{12}=$

If $n$ is an integer which leaves a remainder of $1$ when divided by $3$,then $(1+\sqrt{3}i)^n + (1-\sqrt{3}i)^n$ equals

If $\omega$ is a complex cube root of unity, then the value of $\sin [\pi(\omega^{10} + \omega^{23}) - \frac{\pi}{4}] = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo