If $x^2+y^2=t+\frac{1}{t}$ and $x^4+y^4=t^2+\frac{1}{t^2}$,then $\frac{dy}{dx}$ is equal to

  • A
    $\frac{y}{x}$
  • B
    $\frac{-y}{x}$
  • C
    $\frac{x}{y}$
  • D
    $\frac{-x}{y}$

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