If y=2 sin x+3 cos x and y+A frac{d^2 y}{d x^ | vedclass

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(D) Given $y = 2 \sin x + 3 \cos x$. First,find the first derivative: $\frac{dy}{dx} = 2 \cos x - 3 \sin x$. Next,find the second derivative: $\frac{d

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$1, 0$

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(D) Given $y = 2 \sin x + 3 \cos x$. First,find the first derivative: $\frac{dy}{dx} = 2 \cos x - 3 \sin x$. Next,find the second derivative: $\frac{d^2y}{dx^2} = -2 \sin x - 3 \cos x$. We can rewrite this as $\frac{d^2y}{dx^2} = -(2 \sin x + 3 \cos x) = -y$. Rearranging the equation,we get $y + \frac{d^2y}{dx^2} = 0$. Comparing this with the given equation $y + A \frac{d^2y}{dx^2} = B$,we find $A = 1$ and $B = 0$.

If $y=2 \sin x+3 \cos x$ and $y+A \frac{d^2 y}{d x^2}=B$,then the values of $A$ and $B$ are respectively:

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