જો $2 \sin \left(\theta+\frac{\pi}{3}\right)=\cos \left(\theta-\frac{\pi}{6}\right)$ હોય,તો $\tan \theta=$

  • A
    $\sqrt{3}$
  • B
    $-\frac{1}{\sqrt{3}}$
  • C
    $\frac{1}{\sqrt{3}}$
  • D
    $-\sqrt{3}$

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