If begin{bmatrix} x + y & 2x + z x - y & 2z | vedclass

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(A) Given the matrix equation: $\begin{bmatrix} x + y & 2x + z \ x - y & 2z + w \end{bmatrix} = \begin{bmatrix} 4 & 7 \ 0 & 10 \end{bmatrix}$.By equ

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$x=2, y=2, z=3, w=4$

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(A) Given the matrix equation: $\begin{bmatrix} x + y & 2x + z \ x - y & 2z + w \end{bmatrix} = \begin{bmatrix} 4 & 7 \ 0 & 10 \end{bmatrix}$.By equating the corresponding elements of the two matrices,we get the following system of linear equations:$1) x + y = 4$$2) x - y = 0$$3) 2x + z = 7$$4) 2z + w = 10$From equation $(2)$,we have $x = y$. Substituting this into equation $(1)$,we get $x + x = 4$,which implies $2x = 4$,so $x = 2$. Since $x = y$,we have $y = 2$.Now,substitute $x = 2$ into equation $(3)$: $2(2) + z = 7 \implies 4 + z = 7 \implies z = 3$.Finally,substitute $z = 3$ into equation $(4)$: $2(3) + w = 10 \implies 6 + w = 10 \implies w = 4$.Thus,the values are $x=2, y=2, z=3, w=4$.

If $\begin{bmatrix} x + y & 2x + z \\ x - y & 2z + w \end{bmatrix} = \begin{bmatrix} 4 & 7 \\ 0 & 10 \end{bmatrix}$,then the values of $x, y, z, w$ are

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