If sin {theta _1} + sin {theta _2} + sin {the | vedclass

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(D) Given that $\sin {	heta _1} + \sin {	heta _2} + \sin {	heta _3} = 3$. Since the maximum value of the sine function is $1$,this equation holds t

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(D) Given that $\sin {	heta _1} + \sin {	heta _2} + \sin {	heta _3} = 3$. Since the maximum value of the sine function is $1$,this equation holds true only if $\sin {	heta _1} = 1$,$\sin {	heta _2} = 1$,and $\sin {	heta _3} = 1$. This implies that ${	heta _1} = {	heta _2} = {	heta _3} = \frac{\pi }{2}$. Substituting these values into the expression $\cos {	heta _1} + \cos {	heta _2} + \cos {	heta _3}$,we get: $\cos(\frac{\pi }{2}) + \cos(\frac{\pi }{2}) + \cos(\frac{\pi }{2}) = 0 + 0 + 0 = 0$.

If $\sin {\theta _1} + \sin {\theta _2} + \sin {\theta _3} = 3,$ then $\cos {\theta _1} + \cos {\theta _2} + \cos {\theta _3} = $

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