If $y = \tan^{-1} x$,then . . . . . . .
- A$0 < y < \pi$
- B$0 \leq y \leq \pi$
- C$-\frac{\pi}{2} < y < \frac{\pi}{2}$
- D$-\frac{\pi}{2} \leq y \leq \frac{\pi}{2}$
Explore More
Similar Questions
The domain of the function defined by $f(x) = \cos^{-1} \sqrt{x-1}$ is
The number of real roots of the equation $\tan ^{-1} \sqrt{x(x+1)}+\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{4}$ is:
DifficultJEE MAIN 2021
View SolutionThe range of the real valued function $f(x) = \sin^{-1} ( \frac{1 + x^2}{2 x} ) + \cos^{-1} ( \frac{2 x}{1 + x^2} )$ is
The domain of $f(x) = \frac{1}{{\sqrt {{{\log }_{\frac{\pi }{4}}}({{\sin }^{ - 1}}x) - 1} }}$ is:
The domain of the function $f(x) = \frac{\sin^{-1}(x-3)}{\sqrt{9-x^2}}$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo