If (24, 92) = 24m + 92n,then (m, n) is | vedclass

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(B) To find the greatest common divisor $(24, 92)$,we use the Euclidean algorithm: $92 = 3 	imes 24 + 20$ $24 = 1 	imes 20 + 4$ $20 = 5 	imes 4 + 0

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$(4, -1)$

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(B) To find the greatest common divisor $(24, 92)$,we use the Euclidean algorithm: $92 = 3 	imes 24 + 20$ $24 = 1 	imes 20 + 4$ $20 = 5 	imes 4 + 0$ Thus,$(24, 92) = 4$. Now,express $4$ as a linear combination of $24$ and $92$: $4 = 24 - 1 	imes 20$ Substitute $20 = 92 - 3 	imes 24$: $4 = 24 - 1 	imes (92 - 3 	imes 24)$ $4 = 24 - 92 + 3 	imes 24$ $4 = 4 	imes 24 - 1 	imes 92$ Comparing this with $24m + 92n = 4$,we get $m = 4$ and $n = -1$. Therefore,$(m, n) = (4, -1)$.

If $(24, 92) = 24m + 92n$,then $(m, n)$ is

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