If $f(x) = \begin{cases} \frac{x-|x|}{x}, & x < 0 \\ b\left(\frac{5x^2+a}{x^2-3x+2}\right), & 0 \leq x \leq 1 \\ -14, & x \geq 3 \end{cases}$ is a continuous function on $R$,then $(a, b) =$

  • A
    $\left(2, -\frac{7}{2}\right)$
  • B
    $(2, -14)$
  • C
    $\left(-\frac{7}{2}, -14\right)$
  • D
    $(2, 7)$

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