If A=left[begin{array}{ccc}2 & 0 & -3 4 & 3 | vedclass

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(B) Given $A = \left[\begin{array}{ccc}2 & 0 & -3 \ 4 & 3 & 1 \ -5 & 7 & 2\end{array}ight]$.Any square matrix $A$ can be uniquely expressed as $A

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$\left[\begin{array}{ccc}2 & 0 & -3 \ 4 & 3 & 1 \ -5 & 7 & 2\end{array}ight]$

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(B) Given $A = \left[\begin{array}{ccc}2 & 0 & -3 \ 4 & 3 & 1 \ -5 & 7 & 2\end{array}ight]$.Any square matrix $A$ can be uniquely expressed as $A = P + Q$,where $P = \frac{1}{2}(A + A^T)$ is a symmetric matrix and $Q = \frac{1}{2}(A - A^T)$ is a skew-symmetric matrix.We know that for any symmetric matrix $P$,$P^T = P$,and for any skew-symmetric matrix $Q$,$Q^T = -Q$.Therefore,$P^T - Q^T = P - (-Q) = P + Q = A$.Thus,$P^T - Q^T = A = \left[\begin{array}{ccc}2 & 0 & -3 \ 4 & 3 & 1 \ -5 & 7 & 2\end{array}ight]$.

If $A=\left[\begin{array}{ccc}2 & 0 & -3 \\ 4 & 3 & 1 \\ -5 & 7 & 2\end{array}\right]$ is expressed as a sum of a symmetric matrix $P$ and a skew-symmetric matrix $Q$,then $P^{T}-Q^{T}=$

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