If $f: R \rightarrow R$ is defined by $f(x+y)=f(x)+f(y)$ for all $x, y \in R$ and $f(1)=7$,then $\sum_{r=1}^n f(r)=$

  • A
    $\frac{3 n(n+2)}{4}$
  • B
    $\frac{n(n-1)}{2}$
  • C
    $\frac{7 n(n+1)}{2}$
  • D
    $\frac{(n+1)(n+2)}{4}$

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