If y=a e^x+b e^{-x}+c,where a, b, c are param | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the function $y = a e^x + b e^{-x} + c$. First derivative: $y^{\prime} = \frac{d}{dx}(a e^x + b e^{-x} + c) = a e^x - b e^{-x}$. Second deri

Vedclass · Accepted Answer

$y^{\prime}$

Vedclass · Answer

(C) Given the function $y = a e^x + b e^{-x} + c$. First derivative: $y^{\prime} = \frac{d}{dx}(a e^x + b e^{-x} + c) = a e^x - b e^{-x}$. Second derivative: $y^{\prime \prime} = \frac{d}{dx}(a e^x - b e^{-x}) = a e^x + b e^{-x}$. Third derivative: $y^{\prime \prime \prime} = \frac{d}{dx}(a e^x + b e^{-x}) = a e^x - b e^{-x}$. Comparing this with the first derivative,we see that $y^{\prime \prime \prime} = y^{\prime}$.

If $y=a e^x+b e^{-x}+c$,where $a, b, c$ are parameters,then $y^{\prime \prime \prime}$ is equal to

Similar Questions

For better survival of the human population,which of the following steps is most important?

If the potential at the centre of a uniformly charged ring is $V_0$,then the electric field at its centre will be (assume radius $= R$):

The number of ways that $8$ beads of different colours can be strung as a necklace is

$\lim _{x \rightarrow 0} \frac{\sin x \sin ^{-1} x}{x^2}$ is equal to

The locus of the midpoints of the chords of the parabola $y^2 = 4ax$ which pass through the origin is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module