If $a=2 \hat{i}+3 \hat{j}-5 \hat{k}$,$b=m \hat{i}+n \hat{j}+12 \hat{k}$ and $a \times b=0$,then $(m, n)$ is equal to

  • A
    $\left(\frac{-24}{5}, \frac{-36}{5}\right)$
  • B
    $\left(\frac{-24}{5}, \frac{36}{5}\right)$
  • C
    $\left(\frac{24}{5}, \frac{-36}{5}\right)$
  • D
    $\left(\frac{24}{5}, \frac{36}{5}\right)$

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