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(C) The dimension of Boltzmann constant $A$ is $[M L^2 T^{-2} K^{-1}]$.The dimension of Planck constant $B$ is $[M L^2 T^{-1}]$.The dimension of speed

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stefan’s constant

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(C) The dimension of Boltzmann constant $A$ is $[M L^2 T^{-2} K^{-1}]$.The dimension of Planck constant $B$ is $[M L^2 T^{-1}]$.The dimension of speed of light $C$ is $[L T^{-1}]$.Now,calculate the dimensions of $A^4 B^{-3} C^{-2}$:$= [M L^2 T^{-2} K^{-1}]^4 	imes [M L^2 T^{-1}]^{-3} 	imes [L T^{-1}]^{-2}$$= [M^4 L^8 T^{-8} K^{-4}] 	imes [M^{-3} L^{-6} T^3] 	imes [L^{-2} T^2]$$= [M^{4-3} L^{8-6-2} T^{-8+3+2} K^{-4}]$$= [M^1 L^0 T^{-3} K^{-4}]$.Stefan's constant $\sigma$ is defined by the Stefan-Boltzmann law $E = \sigma T^4$,where $E$ is the energy radiated per unit area per unit time $(E = \frac{	ext{Energy}}{	ext{Area} 	imes 	ext{Time}})$.The dimension of $E$ is $[M L^2 T^{-2}] / [L^2 T] = [M T^{-3}]$.Thus,the dimension of $\sigma = E / T^4 = [M T^{-3}] / [K^4] = [M L^0 T^{-3} K^{-4}]$.Comparing this with the calculated dimension,we find it corresponds to Stefan's constant.

If $A$ represents Boltzmann constant,$B$ represents Planck's constant and $C$ represents speed of light in vacuum,then the quantity having the dimensions of $A^4 B^{-3} C^{-2}$ is

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