If $Z = r(\cos \theta + i \sin \theta), (\theta \neq -\pi / 2)$ is a solution of $x^3 = i$,then $r^9(\cos \theta + i \sin \theta)^9 = $

  • A
    $\frac{\sqrt{3}}{2} + \frac{1}{2} i$
  • B
    $1$
  • C
    $-i$
  • D
    $\frac{-\sqrt{3}}{2} + \frac{1}{2} i$

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