If vec{a} is a non-zero vector of modulus |ve | vedclass

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(C) vector $\vec{v}$ is a unit vector if its magnitude is $1$,i.e.,$|\vec{v}| = 1$. Given that $m\vec{a}$ is a unit vector,we have $|m\vec{a}| = 1$. U

Vedclass · Accepted Answer

$m = \frac{1}{|\vec{a}|}$

Vedclass · Answer

(C) vector $\vec{v}$ is a unit vector if its magnitude is $1$,i.e.,$|\vec{v}| = 1$. Given that $m\vec{a}$ is a unit vector,we have $|m\vec{a}| = 1$. Using the property of the modulus of a scalar multiple of a vector,$|m\vec{a}| = |m| |\vec{a}|$. Therefore,$|m| |\vec{a}| = 1$. Since $m$ is a non-zero scalar,we can write $|m| = \frac{1}{|\vec{a}|}$. Assuming $m$ is positive,$m = \frac{1}{|\vec{a}|}$. Thus,option $(C)$ is the correct condition.

If $\vec{a}$ is a non-zero vector of modulus $|\vec{a}|$ and $m$ is a non-zero scalar,then $m\vec{a}$ is a unit vector if:

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